Subtract (2xy - y² - z²) from the sum of (x² - y² - 3xy - 3yz) and (z² + 2y² - 6xy)
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Answered by
1
Answer:
=x² + 2y² + 2z² - 3yz - 11xy
Step-by-step explanation:
(x² - y² - 3xy -3yz) + (z² + 2y² - 6xy) - (2xy - y² - z²)
= (x² + y² + z² - 3yz - 9xy) - 2xy + y² + z²
= x² + 2y² + 2z² - 3yz - 11xy
Answered by
1
Subtract (2xy - y² - z²) from the sum of (x² - y² - 3xy - 3yz) and (z² + 2y² - 6xy)
= (x² - y² - 3xy - 3yz) + (z² + 2y² - 6xy) - (2xy - y² - z²)
= x² - y² - 3xy - 3yz + z² + 2y² - 6xy - 2xy + y² + z²
= x² + 2y² + 2z² - 11xy - 3yz
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