Question

subtract: 2y² + 5z² - 2y - 6z from 12y² + 28z²-7z + 5​

Answer 1

3x^2+2y^2-(2x^2-3y^2)
3x^2+2y^2-2x^2+3y^2
x^2+5y^2 Ans

Answer 2

Solution:-

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$\implies$ Here, it is given in the question that we have subtract 2y² + 5z² - 2y - 6z from 12y² + 28z²-7z + 5. Now, we will find its difference. So, to solve this follow the steps shown below.

ANSWER:-

❖ Subtracting 2y² + 5z² - 2y - 6z from 12y² + 28z²-7z + 5 gives 10y² + 23z² - z + 5 + 2y.

GIVEN:-

➙ Minuend = 12y² + 28z²-7z + 5

➙ Subtrahend = 2y² + 5z² - 2y - 6z

TO FIND:-

⇢ Difference = ?

SOLVING STEP BY STEP:-

➙ Minuend = 12y² + 28z²-7z + 5

➙ Subtrahend = 2y² + 5z² - 2y - 6z

• Subtracting:-

↣ 12y² + 28z²-7z + 5 - (2y² + 5z² - 2y - 6z)

↣ 12y² + 28z²-7z + 5 - 2y² - 5z² + 2y + 6z

↣ 12y² - 2y² + 28z² - 5z² - 7z + 6z + 5 + 2y

↣ 10y² + 23z² - z + 5 + 2y

Thus, we got the answer. Subtracting 2y² + 5z² - 2y - 6z from 12y² + 28z²-7z + 5 gives 10y² + 23z² - z + 5 + 2y.

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