Math, asked by pgidde003, 10 days ago

Subtract: -3/7x^2y - 1/3x^2y​

Answers

Answered by sarthakagarwal8c4482
0

Answer:

That's -16/21x^2y

Step-by-step explanation:

-3/7x^2y and 1/3x^2y

take lcm as -- 21x^2y

then multiply 3 in -> -3/7x^2y

u will get -9/21x^2y

Now, multiply 7 in  1/3x^2y

u will get 7/21x^2y

now subtract,

(-9-7)/21x^2y

then ur answer is -16/21x^2y

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Answered by aparnayadavindore
0

Answer:

Hii, Here is your answer:

Step-by-step explanation:

Given:

7x−2y=1 ...(1)

3x+4y=15 .... (2)

First multiply the first equation by 2:

We got, 14x−4y=2

Now add the first and second equation:

14x−4y+3x+4y=15+2

17x=17

so, x=1

By putting x in any equation we got;

y=3

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