Subtract 3 a(a+b+c) from 26 (9-b+c)
Answers
Answered by
0
Step-by-step explanation:
4c(−a+b+c)−[3a(a+b+c)−2b(a−b+c)]
4c(−a+b+c)−[3a
2
+3ab+3ac−2ab+2b
2
−2bc]
4c(−a+b+c)−[3a
2
+2b
2
+ab+3ac−2bc]
−4ac+4bc+4c
2
−3a
2
−2b
2
−ab−3ac+2bc
4c
2
−3a
2
−2b
2
−ab+6bc−7ac
Answered by
0
Answer:
26(9-b+c)-3a(a+b+c)
234-26b+26c-3^2-3ab-3ac
Step-by-step explanation:
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