Math, asked by mahajanpaavani3030, 1 day ago

Subtract 3(ab-bc-ca) from (-ab-bc-ca)

Answers

Answered by suhail2070

1

Answer:

$- 4ab + 2bc + 2ca.$

Step-by-step explanation:

$( - ab - bc - ca) -3 (ab - bc - ca) \\ \\ = - 4ab + 2bc + 2ca.$

Answered by uttambera538

2

-ab - bc - ca - 3(ab - bc - ca)

= - ab - bc - ca - (+ 3ab - 3bc - 3ac)

= -ab - bc - ca - 3ab + 3bc + 3ac

= (-1 - 3)ab + (-1 + 3)bc + (-1 + 3) ac

= -4ab + 2bc + 2ac

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