Question

Subtract :- 3a (10c-3b+2a) from 4a (a-4b+5c)​

Answer 1

$\huge \fbox \red{an} \fbox \green{s} \fbox \pink{we} \fbox \purple{r}$

It is instructed to subtract (2a−3b+4c) from the sum of (a+3b−4c),(4a−b+9c) and (−2b+3c−a).

So, First we will do the sum of the three given polynomials,

Sum =(a+3b−4c)+(4a−b+9c)+(−2b+3c−a)

=(a+4a−a)+(3b−b−2b)+(−4c+9c+3c)

=4a+8c

$\huge\underline{\overline{\mid{\green{Now, \: we \: can \: perform \: the \: subtraction,}}}}$

∴  Required difference

=(4a+8c)−(2a−3b+4c)

=4a+8c−2a+3b−4c

=2a+3b+4c

$\huge \boxed{ \colorbox{lime}{hope \: this \: helps}}$

Answer 2

Answer:

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Step-by-step explanation: