subtract 3a^2-1/3a+1 from 7/3a^2+7a-8
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Solution :-
→ {7/(3a² + 7a - 8)} - {(3a² - 1)/(3a + 1)}
taking LCM,
→ {7(3a + 1) - (3a² - 1)(3a² + 7a - 8)}/(3a² + 7a - 8)(3a + 1)
→ {(21a + 7) - (9a⁴ + 21a³ - 24a² - 3a² - 7a + 8)} / (9a³ + 21a² - 24a + 3a² + 7a - 8)
→ (21a + 7 - 9a⁴ - 21a³ + 24a² + 3a² + 7a - 8) / (9a³ + 24a² + 31a - 8)
→ (-9a⁴ - 21a³ + 27a² + 28a - 1) / (9a³ + 24a² + 31a - 8) (Ans.)
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