Question

subtract 3a^2bc‐2a^2c+4abc^2 from the sum of 2a^2bc+ab^2c‐3abc^2 and a^2bc‐2ab^2c+abc^2​

Answer 1

Answer:

1 answer

Subtract 2ab^2c^2 + 4a^2b^2c - 5a^2bc^2 from - 10a^2b^2c + 4ab^2c^2 + 2a^2bc^2

Top answer · 3 votes

- 10a^2b^2c + 4ab^2c^2 + 2a^2bc^2 - (2ab^2c^2 + 4a^2b^2c - 5a^2bc^2) - 10a^2b^2c + 4ab^2c^2 + 2a^2bc^2 - 2ab^2c^2 - 4a^2b^2c + 5a^2bc^2 = - 10a^2b^2c - ... More

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Answer 2

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