Math, asked by mitali4424, 1 year ago

Subtract 3a-4b+3c from the sum of 5a+ab -3c and 3a-2b+5c

Answers

Answered by mysticd
6

Answer:

5a+ab+2b+2c

Step-by-step explanation:

Let A = 3a-4b+3c,

B= 5a+ab-3c and

C = 3a-2b+5c

/* According to the problem given,

B+C-A

= (5a+ab-3c+3a-2b+5c)-(3a-4b+3c)

= 8a+ab-2b+5c-3a+4b-3c

= 5a+ab+2b+2c

Answered by Anonymous
1

Solution:-

According to the question-

(3a - 4b +3c ) is Subtracted from the sum of (5a + ab - 3c) and (3a - 2b +5c)

Hence,

→ (5a +ab - 3c+3a -2b+5c )-(3a - 4b +3c )

→ 8a +ab + 2c - 3a + 4b - 3c

→ 5a +ab + 2b - c

This is the required Solution.

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