Subtract 3a-4b+3c from the sum of 5a+ab -3c and 3a-2b+5c
Answers
Answered by
6
Answer:
5a+ab+2b+2c
Step-by-step explanation:
Let A = 3a-4b+3c,
B= 5a+ab-3c and
C = 3a-2b+5c
/* According to the problem given,
B+C-A
= (5a+ab-3c+3a-2b+5c)-(3a-4b+3c)
= 8a+ab-2b+5c-3a+4b-3c
= 5a+ab+2b+2c
•••♪
Answered by
1
Solution:-
According to the question-
(3a - 4b +3c ) is Subtracted from the sum of (5a + ab - 3c) and (3a - 2b +5c)
Hence,
→ (5a +ab - 3c+3a -2b+5c )-(3a - 4b +3c )
→ 8a +ab + 2c - 3a + 4b - 3c
→ 5a +ab + 2b - c
This is the required Solution.
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