Subtract 3a-4b+5c-1 from the sum of 4a+3b-3c+2 and 5a-6b-5.
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Sum of −2a+b−5c and 3a−2b+c
−2a+b−5c+3a−2b+c=a−b−4c
Subtracting 3a−2b+4c from a−b−4c
a−b−4c−(3a−2b+4c)
=a−b−4c−3a+2b−4c
=−2a+b−8c
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