subtract 3a‐5b+5c from the sun of 2a+3b and 3a‐2b‐3c
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=(2a+3b) + (3a-2b-3c)
= 2a +3b +3a-2b-3c
= 5a+1b-3c
Now subtracting both expressions:
= (5a +1b-3c) - (3a-5b +5c)
= 5a + 1b - 3c - 3a +5b - 5c
= 2a+6b - 8c
Hope it helps you.
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