subtract 3a‐5b+5c from the sun of 2a+3b and 3a‐2b‐3c
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(2a+3b ) + ( 3a-2b-3c) = 2a+3a+3b-2b-3c
= 5a +b -3c
now we have to subtract 3a-5b+5c
required answer is.
(5a+b-3c) -(3a-5b+5c)
= 5a-3a+b+5b-3c-5c
= 2a+6b-8c is the required correct answer. hope it helps!
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