Question

subtract : 3a(a+2b+c)+2b(a-b) from 4c(-a+b-c)​

Answer 1

Given: The equation is $3a(a+2b+c)+2b(a-b)$and$4c(-a+b-c)$.

We have to subtract $3a(a+2b+c)+2b(a-b)$from$4c(-a+b-c)$.

• As we know that the subtraction is an arithmetic operation that represents the operation of removing objects from a collection.
• Subtraction is denoted by the minus(-) sign.
• By using the properties of subtraction, we are solving the above equation.

We are solving in the following way:

We have,

$3a(a+2b+c)+2b(a-b)$and$4c(-a+b-c)$.

Simplifying the equation$3a(a+2b+c)+2b(a-b)$:

$=>3a^2+6ab+3ac+2ab-2b^2$

Now, subtracting $3a^2+6ab+3ac+2ab-2b^2$from$4c(-a+b-c)$:

$=>4c(-a+b-c)-(3a^2+6ab+3ac+2ab-2b^2)\\=>-4ca+4cb-4c^2-3a^2-6ab-3ac-2ab+2b^2\\=>-4c^2-3a^2+2b^2-8ab-7ca$

Hence, after subtracting $3a^2+6ab+3ac+2ab-2b^2$from$4c(-a+b-c)$ we get$-4c^2-3a^2+2b^2-8ab-7ca$.