Subtract : 3a(a + b + c) – 26(a – b + c) from 4c(-a + b + c)
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4c(−a+b+c)−[3a(a+b+c)−2b(a−b+c)]
4c(−a+b+c)−[3a 2 +3ab+3ac−2ab+2b 2−2bc]
4c(−a+b+c)−[3a 2 +2b 2 +ab+3ac−2bc]
−4ac+4bc+4c 2 −3a 2 −2b 2 −ab−3ac+2bc
4c 2 −3a 2 −2b 2 −ab+6bc−7ac
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