subtract 3a(a+b-c)-2b(a-b+c)from 4c(-a+b+c).
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Answer:
-3a²-2b²+4c²-ab+6bc-ac
Step-by-step explanation:
Let p = 3a(a+b-c)-2b(a-b+c)
q = 4c(-a+b+c).
According to the problem given,
q-p
= 4c(-a+b+c)-[3a(a+b-c)-2b(a-b+c)]
= -4ac+4bc+4c²-(3a²+3ab-3ac-2ab+2b²-2bc)
= -4ac+4bc+4c²-3a²-3ab+3ac+2ab-2b²+2bc
= -3a²-2b²+4c²-3ab+2ab+4bc+2bc-4ac+3ac
= -3a²-2b²+4c²-ab+6bc-ac
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