Subtract
3a(a+b+c)-2b(a-b+c) from - 4c(a-b-c)
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Answer:
-3a^2-2b^2+4c^2-7ac+6bc-ab
Step-by-step explanation:
- 4c(a-b-c)-{3a(a+b+c)-2b(a-b+c)}
=-4ca+4bc+4c^2-{3a^2+3ab+3ac-(2ab-2b^2+2bc)}
=-4ca+4bc+4c^2-{3a^2+3ab+3ac-2ab+2b^2-2bc}
=-4ca+4bc+4c^2-{3a^2+ab+3ac+2b^2-2bc}
=-4ca+4bc+4c^2-3a^2-ab-3ac-2b^2-2bc
=-7ac+6bc+4c^2-3a^2-ab-2b^2
=-3a^2-2b^2+4c^2-7ac+6bc-ab ANS
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