Question

Subtract : 3a(a+b+c)—2b(a-b+c) from 4c(-a+b+c)

Answer 1

$\large\bf\underline {To \: find:-}$

we need to subtract : 3a(a+b+c)—2b(a-b+c) from 4c(-a+b+c).

$\huge\bf\underline{Solution:-}$

➻ 4c( - a + b +c)-[3a(a + b + c) - 2b( a - b + c)]

➻ - 4ac + 4bc + 4c² -[3a² + 3ab + 3ac) - 2ab + 2b² - 2bc ]

➻ -4ac + 4bc + 4c² - 3a² - 3ab + 3ac + 2ab - 2b² + 2bc

➻ - ac + 6bc - ab - 3a² - 2b² + 4c²

➻ 4c²- 3a² + 6bc - ab - ac

Hence,

4c( - a + b +c)-[3a(a + b + c) - 2b( a - b + c) = 4c²- 3a² + 6bc - ab - ac .

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Answer 2

REMAINING 2 STEPS ARE BELOW ↓

= 7ac + 6bc + 4c² - 3a²

Therefore,

• −3a2 −2b2 + 4c2 − ab + 6bc − 7ac.