subtract 3a (a+b+c)-2b(a-b-c) from 4c(-a+b+c)
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2
Step-by-step explanation:
ANSWER
4c(−a+b+c)−[3a(a+b+c)−2b(a−b+c)]
4c(−a+b+c)−[3a
2
+3ab+3ac−2ab+2b
2
−2bc]
4c(−a+b+c)−[3a
2
+2b
2
+ab+3ac−2bc]
−4ac+4bc+4c
2
−3a
2
−2b
2
−ab−3ac+2bc
4c
2
−3a
2
−2b
2
−ab+6bc−7ac
Answered by
0
Answer:c(−a+b+c)−[3a(a+b+c)−2b(a−b+c)]
4c(−a+b+c)−[3a
2
+3ab+3ac−2ab+2b
2
Step-by-step explanation: Will u be my friend
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