Subtract : 3a(a+b+c) - 2b(a-b+c) from 4c(-a+b+c).
Answers
Answered by
774
4c(-a+b+c) - [3a(a+b+c)-2b(a-b+c)]
=-4ac+4bc+4c²-[3a²+3ab+3ac-2ab+2b²-2bc]
=-4ac+4bc+4c²-3a²-3ab-3ac+2ab-2b²+2bc
write like terms at one place
=-4ac-3ac+4bc+2bc+4c²-3a²-2b²-3ab+2ab
=-7ac+6bc-ab+4c²-3a²-2b²
=-4ac+4bc+4c²-[3a²+3ab+3ac-2ab+2b²-2bc]
=-4ac+4bc+4c²-3a²-3ab-3ac+2ab-2b²+2bc
write like terms at one place
=-4ac-3ac+4bc+2bc+4c²-3a²-2b²-3ab+2ab
=-7ac+6bc-ab+4c²-3a²-2b²
Answered by
169
Answer:
Step-by-step explanation:
Question: 3a(a+b+c) - 2b(a-b+c) from
4c(-a+b+c)
= -4ac + 4bc + 4c² - 3a² - 3ab - 3ac + 2ab - 2b² + 2bc
Now, put all the like terms next to each other.
= -4ac - 3ac + 4bc + 2bc + 4c² - 3a² - 2b² - 3ab + 2ab
= -7ac + 6bc - ab + 4c² - 3a² - 2b²
Hope you got your answer correct .
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