Question

Subtract 3a(a+b+c)-2b(a-b-c)from4c(-a+b+c)

Answer 1

Answer:

3a (a + b + c) − 2b (a − b + c) = 3a2 +3ab + 3ac − 2ba + 2b2 − 2bc = 3a2 + 2b2 + ab + 3ac − 2bc 4c (− a + b + c) = − 4ac + 4bc + 4c2 Subtracting these expressions, we obtain Therefore, the result is −3a2 −2b2 + 4c2 − ab + 6bc − 7ac

Answer 2

Step-by-step explanation:

$★ \: 3a(a + b + c) - 2b(a - b + c) \\ = 3a {}^{2} + 3ab + 3ac - 2ab + 2b {}^{2} - 2bc \\ = 3a {}^{2} + 2b {}^{2} + ab - 2bc + 3ac \\ ★And \: 4c( - a + b + c) = - 4ac + 4bc + 4c {}^{2}$

★ SuBtRaCtInG ★

$★ ( - 4ac + 4bc + 4c</u></strong><strong><u> </u></strong><strong><u>{}^{2} - (3a {}^{2} + 2b {}^{2} + ab - 2bc + 3ac) \\ = - 4ac + 4bc + 4c {}^{2} - 3a {}^{2} - 2b {}^{2} - ab + 2bc - 3ac \\ = ( - 4ac - 3ac) + (4bc + 2bc) - ab - 3a {}^{2} - 2b {}^{2} + 4c {}^{2} \\ = - 7ac - 6bc - ab - 3a {}^{2} - 2b {}^{2} + 4c {}^{2}$

= - 3a² - 2b² + 4c - ab + 6bc - 7ac.

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