Subtract 3a²+4ab+b² from the sum of a²-b² and 2a²+3ab-2b²
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a²-b²+2a²+3ab-2b²-3a²-4ab-b²
=3a²-3a²-4b²-ab
=-4b²-ab
Answered by
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Answer:
3ab-4ab²-4a²-4b2
Step-by-step explanation:
a²-b²+2a²+3ab-²b²
3ab-a²-3b²-(3a²+4ab²+b²)
3ab-a²-3b²-3a²-4ab²-b²
3ab-4ab-a²-3a²-3b²-b²
= 3ab-4ab²-4a²-4b²
Hope it will help you...
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=3a²-3a²-4b²-ab
=-4b²-ab