Question

Subtract (3a²-5a+5) and (a³-5a²+8) from (7a² -4a² - 9)

Answer 1

Hello Hasan


Your answer


First Add,
(3a²-5a+5)+ (a³-5a²+8)
= 3a²-5a+5+a³-5a²+8
= a³+3a²-5a²+5+8
= a³-2a²+13

And now,
Subtract a³-2a²+13 from 7a²-4a²-9
= 7a²-4a²-9 - (a³-2a²+13)
= 7a²-4a²-9-a³+2a²-13
= - a³+7a²-4a²+2a²-9-13
= - a³+5a²-22 ans.✅✅



If it helps you mark me as a brainlist

Thanks
❤️❤️