Math, asked by ssharsh3222, 8 months ago

subtract 3ab (a-b) from 2ab(a+b)

Answers

Answered by Anonymous
291

Answer :- -a²b + 5ab²

Solution

⟹ 2ab (a+b) - 3ab (a-b)

⟹ 2a²b + 2ab² - 3a²b + 3ab²

⟹ 2a²b - 3a²b + 2ab² + 3ab²

⟹ -a²b + 5ab²

Thus, Subtracted

Answered by pulakmath007
2

Subtraction of 3ab (a-b) from 2ab(a+b) gives 5ab² - a²b

Given :

The expressions 3ab (a-b) and 2ab(a+b)

To find :

The subtraction

Solution :

Step 1 of 2 :

Write down the given expressions

The given expressions are 3ab (a-b) and 2ab(a+b)

Step 2 of 2 :

Subtract the expressions

On subtraction we get

 \sf 2ab (a+b) - 3ab (a-b)

 \sf  = (2 {a}^{2} b + 2a {b}^{2} ) - (3 {a}^{2} b - 3a {b}^{2} )

 \sf  = 2 {a}^{2} b + 2a {b}^{2}  - 3 {a}^{2} b  +  3a {b}^{2}

 \sf  = 2a {b}^{2}   +  3a {b}^{2}  + 2 {a}^{2} b  - 3 {a}^{2} b

 \sf  =( 2 + 3)a {b}^{2}  + (2  - 3) {a}^{2} b

 \sf  =5a {b}^{2}   -  {a}^{2} b

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