subtract 3abc -a2-b2 from c2+2a2-b2+abc
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Answered by
8
hello users ...
we have to subtract :
3abc - a² - b² from c² + 2a² - b² + abc
solution:-
=> (c² + 2a² - b² + abc) - (3abc - a² - b²)
= [ c² + 2a² - b² + abc - 3abc + a² + b² ]
= [3a² + c² -2ab] Answer
# hope it helps :)
we have to subtract :
3abc - a² - b² from c² + 2a² - b² + abc
solution:-
=> (c² + 2a² - b² + abc) - (3abc - a² - b²)
= [ c² + 2a² - b² + abc - 3abc + a² + b² ]
= [3a² + c² -2ab] Answer
# hope it helps :)
Answered by
1
Answer:
374+_";(#(_(3@?(_)272(₹++3()_!(3
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