Question

Subtract : 3k(5kl+3m) from 6k(2k+3l2m)​

Answer 1

Answer:

-3k2+ 21kl-21k2m2

Step-by-step explanation:

Here we have 3k(5k−l + 3m) and 6k(2k + 3l−2m)

Using the distributive law 3k(5k−l + 3m) = 15k2-3kl + 9km

and 6k(2k + 3l-2m) = 12k2 + 18kl-12km

Now , we have to subtract 15k2-3kl + 9km from 12k2 + 18kl-12km.

i.e. (12k2 + 18kl-12km)-(15k2-3kl + 9km) = -3k2 + 21kl-21k2m2

Hence after subtraction of the product of 3k(5k−l + 3m) from the product of 6k(2k + 3l−2m) is =-3k2+ 21kl-21k2m2

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Answer 2

6k(2k+312m) - 3k(5kl + 3m)

12k2 + 1872km - 15k2l - 9km

12k2 - 15k2l + 1872km - 9km

12k2 - 15k2l + 1863km (ans)

ANSWER IS 12k2 - 15 k2l + 1863km