Question

subtract : 3l(l-4m+5n) from 4l(10n-3m+21)​

Answer 1

On subtracting 3l(l-4m+5n) from 4l(10n-3m+2l) we get 5l^2+25ln.

The steps are as follow:---

i】We need to subtract 3l(l-4m+5n)from 4l(10n-3m+2l)

ii】So 4l(10n-3m+2l)-3l(l-4m+5n)

=40ln -12lm+8l^2-(3l^2-12lm+15ln)

=40ln-12lm+8l^2-3l^2+12lm-15ln

iii】Rearranging we have

=8l^2-3l^2+40ln-15ln-12lm+12lm

=5l^2+25ln+0

=5l^2+25ln

=5l(l+5n).

So on subtracting we get answer as

5l^2+25ln