Math, asked by sarvinkhawasia, 8 months ago

Subtract −3p 2 + 3pq from 3p (−p − a − r)

Answers

Answered by Anonymous
2

Answer:

Step-by-step explanation:

Pull out like factors :

-p - a - r  =   -1 • (p + a + r)

((0-(3•(p2)))+3pq)--3p•(p+a+r)

((0 -  3p2) +  3pq) -  -3p • (p + a + r)

Pull out like factors :

  3pq + 3pa + 3pr  =   3p • (q + a + r)

Final result :

 3p • (q + a + r)

Answered by abiswasthikas66
0
ANSWER
We subtract the given expression 4p
2
q−3pq+5pq
2
−8p+7q−10 from 18−3p−11q+5pq−2q
2
+5p
2
q as shown below:

(18−3p−11q+5pq−2q
2
+5p
2
q)−(4p
2
q−3pq+5pq
2
−8p+7q−10)
=18−3p−11q+5pq−2q
2
+5p
2
q−4p
2
q+3pq−5pq
2
+8p−7q+10
=(18+10)+(−3p+8p)+(−11q−7q)+(5pq+3pq)−2q
2
+(5p
2
q−4p
2
q)−5pq
2

(Combiningliketerms)
=28+5p−18q+8pq−2q
2
+p
2
q−5pq
2


Hence, (18−3p−11q+5pq−2q
2
+5p
2
q)−(4p
2
q−3pq+5pq
2
−8p+7q−10)=28+5p−18q+8pq−2q
2
+p
2
q−5pq
2
.
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