subtract 3pq(p-q) from 2pq(p+q)
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Answered by
15
Answer:
2pq(p+q) - 3pq(p-q) = 5pq² - p²q
Step-by-step explanation:
Let first expression : 3pq(p-q),
Second expression : 2pq(p+q)
/* According to the problem given,
Subtracting first expression from second expression = 2pq(p+q) - 3pq(p-q)
= 2p²q + 2pq² - 3p²q + 3pq²
= 2pq² + 3pq² + 2p²q - 3p²q
= (2+3)pq² + (2-3)p²q
= 5pq² - p²q
Therefore,
2pq(p+q) - 3pq(p-q) = 5pq² - p²q
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2
Answer:
here is your answer dude
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