Math, asked by anandsinghrathia3101, 7 months ago

subtract 3pq(p-q) from 2pq(p+q)​

Answers

Answered by kotapatiharsha
2

Step-by-step explanation:

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Answered by Anonymous
5

\bigstar Question:

  • Subtract 3pq(p-q) from 2pq(p+q).

\bigstar Solution:

First of all, let's find the value.

3pq( p - q ) = 3p²q - 3pq²

Now, 2pq( p + q ) = 2p²q + 2pq²

Now by subtracting 3p²q - 3pq² from 2p²q + 2pq² we get,

2p²q + 2pq² - (3p²q - 3pq²)

\implies2p²q + 2pq² - 3p²q + 3pq²

(Negative × Negative = Positive)

\implies2p²q - 3p²q + 3pq² + 2pq²

\implies (- p² q) + 5pq²

\implies 5pq² - p²q

\bigstar Answer:

  • Therefore, the result will be 5pq² - p²q.
  • You can also write 5pq² - p²q

\rightarrow pq( 5q - p)

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