subtract 3pq(p-q) from 2pq(p+q)
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Question:
- Subtract 3pq(p-q) from 2pq(p+q).
Solution:
First of all, let's find the value.
3pq( p - q ) = 3p²q - 3pq²
Now, 2pq( p + q ) = 2p²q + 2pq²
Now by subtracting 3p²q - 3pq² from 2p²q + 2pq² we get,
2p²q + 2pq² - (3p²q - 3pq²)
2p²q + 2pq² - 3p²q + 3pq²
(Negative × Negative = Positive)
2p²q - 3p²q + 3pq² + 2pq²
(- p² q) + 5pq²
5pq² - p²q
Answer:
- Therefore, the result will be 5pq² - p²q.
- You can also write 5pq² - p²q
pq( 5q - p)
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