Question

Subtract 3pq (p - q) from 2pq (p+q).​

Answer 1

Answer:

3pq(p-q)-2pq(p+q)

'pq' is common factor

= pq( 3(p-q) -2(p+q) )

= pq(3p-3q-2p-2q)

= pq(p-5q)

= p^2q - 5pq^2

Answer 2

5pq^2 - p^2q.

= 2pq ( p+q ) - {3pq ( p- q )}.

= 2p^2q + 2pq^2 - { 3p^2q - 3pq^2 }.

( multiplying them one by one ).

= 2p^2q + 2pq^2 - 3p^2q + 3pq^2.

( opening the brackets - The minus sign changes into plus sign ).

= 2p^2q - 3p^2q + 2pq^2 + 3pq^2.

( collecting the like terms ).

= -p^2q + 5pq^2.

Now rearranging :

= 5pq^2 - p^2q.

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