Subtract 3pq (p-q) from 2pq (p+q) (With steps please!)
Answers
Answered by
1
Answer:
-p2q+5pq2
Step-by-step explanation:
= 2p²q + 2pq² - 3p²q + 3pq²
= 2pq² + 3pq² + 2p²q - 3p²q
= (2+3)pq² + (2-3)p²q
= 5pq² - p²q
Answered by
1
Answer:
-pq(p+q)
Step-by-step explanation:
3pq(p-q) = (3p²q + 3pq²) - eq 1
2pq(p+q) = (2p²q + 2pq²) - eq 2
Subtract eq 1 from eq 2
=> (2p²q + 2pq²) - (3p²q + 3pq²)
=> 2p²q + 2pq² - 3p²q - 3pq²
=> 2p²q-3p²q + 2pq²-3pq²
=> -p²q-pq²
In both the terms -pq is common.
=> -pq(p+q)
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