Question

subtract 3x^2y^2-10+6y^2 from the sum of 4x^2-15+3y^2-9x^2y^2 and 8x^2y^2-3+x^3

plz answer it​

Answer 1

Answer:

4x² - 3y² - 4x²y²- 8

Step-by-step explanation:

• sum of 4x^2-15+3y^2-9x^2y^2 and 8x^2y^2-3+x^3

$(4x^2-15+3y^2-9x^2y^2) + (8x^2y^2-3+x^3)\\4x^2-15+3y^2-9x^2y^2 + 8x^2y^2-3+x^3\\\\-15-3+4x^{2} +3y^{2} - 9x^2y^2+ 8x^2y^2\\-18+4x^{2}+3y^{2}-1x^2y^2$

• subtract 3x^2y^2-10+6y^2 from the sum

$(-18 + 4x^{2} +3y^{2} -1x^{2} y^{2}) - (3x^2y^2-10+6y^2)\\-18 + 4x^{2} +3y^{2} -1x^{2} y^{2} - 3x^2y^2 + 10 - 6y^2\\-18+10+4x^{2}+3y^{2}- 6y^2-1x^{2} y^{2} - 3x^2y^2\\-8+4x^{2}-3y^{2}-4x^{2} y^{2}\\4x^{2}-3y^{2}-4x^{2} y^{2}-8$

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Answer 2

Step-by-step explanation:

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