Math, asked by pratima6204, 2 months ago

subtract (3x-5y+z)from the sum of (x+4y-z), (5x-3y+2z) and (-3x+2y-9z)​

Answers

Answered by Anonymous
2

Answer:

8y-9z

Step-by-step explanation:

Sum of (x+4y-z), (5x-3y+2z) and (-3x+2y-9z)​ => (x+4y-z) + (5x-3y+2z) +(-3x+2y-9z)

= x+4y-z+5x-3y+2z + -3x+2y-9z

= x+5x-3x + 4y-3y+2y - z+2z-9z

= 3x + 3y - 8z

Subtracting (3x-5y+z) from 3x+3y-8z

= 3x+3y-8z - (3x-5y+z)

= 3x+3y-8z - 3x+5y-z

= 8y-9z

Answered by prasantasamanta4861
1

{(x+4y-z)+(5x-3y+2z)+(-3x+2y-9z)} - (3x-5y+z)

={x+ 4y-z+5x-3y+2z-3x +2y-9z} -(3x -5y+z)

={3x +3y-8z}-(3x-5y+z)

=3x+3y-8z-3x+5y-z

=8y-9z

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