Question

subtract 3x (x-y-z) + 3 y (x-y+z) +3z(x+y-z)
from . 3 (x+y)(x- y) + 3z (2 y+ z)
tell fast​

Answer 1

Answer:

$6z^2$

Step-by-step explanation:

3 (x+y)(x- y) + 3z (2 y+ z) - [3x (x-y-z) + 3 y (x-y+z) +3z(x+y-z)]

$3 (x^{2} - y{2}) + 6yz+ 3z^{2} - [3x^{2}-3xy-3xz + 3xy-3y^2+3yz +3xz+3yz-3z^2]$

$3x^{2} - 3y{2} + 6yz+ 3z^{2} - 3x^{2}+3xy+3xz - 3xy+3y^2-3yz -3xz-3yz+3z^2$

$3x^{2}- 3x^{2} - 3y{2} +3y^2 +3z^2+ 3z^{2} +3xy- 3xy + 6yz-3yz-3yz+3xz -3xz-3yz -3yz$

$6z^2$