Math, asked by tanancymRr4a, 1 year ago

Subtract:3x (x-y-z) + 3y (x-y+z) + 3z (x+y-z) from 3 (x+y)(x-y) + 3z (2y+z)

Answers

Answered by Madhu237

3x²-3y²+6yz+3z²-(3x²-3xy- 3xz+ 3xy-3y²+3yz+3xz+3yz-3z²)= 6z²

Answered by AdityaBhargavSingh

Answer:

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⭐ ANSWER

3x²-3y²+6yz+3z²-(3x²-3xy-3xz+3xy-3y²+3yz-3xz+3yz-3z²) = 6z²

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