Question

Subtract (3x2 – 2x + 5xy - 7) from (8 - 9xy + 3x2 - 5x)

Answer 1

Answer:

Arrange the terms.

Step-by-step explanation:

Remove the bracket

$8 - 9xy + 3x {}^{2} - 5x - (3x {}^{2} - 2x + 5xy - 7) \\ = 8 - 9xy + 3x {}^{2} - 5x - 3x {}^{2} + 2x - 5xy + 7 \\ = 15 - 14xy - 3x$

Answer 2

Answer:

$=-14xy-3x+15$

Step-by-step explanation:

Given: Subtract $($$3x^{2}-2x + 5xy - 7$$)$ from $(8 - 9xy + 3x^{2} - 5x)$

Firstly, we will arrange the variable according to their order

Subtract $(3x^{2} + 5xy -2x - 7)$ from $(3x^{2} - 9xy - 5x+8)$

Now,

$(3x^{2} - 9xy - 5x+8)$ $- (3x^{2} + 5xy -2x - 7)$

On opening the brackets,

$=3x^{2} - 9xy - 5x+8- 3x^{2} - 5xy +2x +7$

Solving this will result into cancelling 3$x^{2}$ with each other as they both are in opposite signs ( -3$x^{2}$ and 3$x^{2}$ ).

Now,

On further solving,

$-9xy$ and $-5xy$ will be added together as they have same negative sign and we know that digits with same negative sign get added and sign will be negative.

So,

$=-14xy- 5x+8+2x +7$

Here, again -5x and 2x will be subtracted as negative sign and positive sign lead to subtraction and the sign will be negative because the larger digit has negative sign.

After adding 8 and 7, we will get 15

Now on solving it

$=-14xy-3x+15$

Hence, On subtracting $(3x^{2}-2x + 5xy - 7)$ from $(8 - 9xy + 3x^{2} - 5x)$

We will get $=-14xy-3x+15$

For more such inormation: https://brainly.in/question/32571977

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