Math, asked by sangnikbanerjee, 9 months ago

Subtract 3x2+5y2-2y2 from the sum of 5y2+3z2 and 2x2-3y2

Answers

Answered by ms8120584
1

the sum of (5y²+3z²)+ (2x²-3y²)

is 2x²2y²+3z²

the difference is (3x²+5y²-2y²) - (2x²2y²+3z²)

is (x²+7y²-5z²

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