Math, asked by fatemataskeen79, 1 day ago

Subtract 3y2 + 2yz from y2 + 5yz +z 2​

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Answered by gourangamudi299
7

Your answer:

y² + 5yz + z² - (3y² + 2yz)

= y² + 5yz + z² - 3y² - 2yz

= y² - 3y² + 5yz - 2yz + z²

= -2y² + 3yz + z²

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