Question

Subtract: 4 2 – 3 + 5 2 – 8 + 7 – 10 18 – 3 – 11 + 5 – 2 2 + 5 2 and hence find the value of expression at p = 1and q = - 1​

Answer 1

Step-by-step explanation:

Subtracting (4p2q−3pq+5pq2−8p+7q−10) from (18−3p−11q+5pq−2pq2+5p2q)

we have,

                 = (18−3p−11q+5pq−2pq2+5p2q)−(4p2q−3pq+5pq2−8p+7q−10) 

                 = 18−3p−11q+5pq−2pq2+5p2q−

7p2q+3pq−5pq2+8p−7q+10 

                 = 28+5p−78q+8pq−7pq2+p2q

p²q