Subtract 40a+20b-90c from 20a-40b
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Step-by-step explanation:
Given: #1 A + B = 50, #2 B + C = 30 & #3 C + A = 40
A+B=50 (#1 given)
-B-C=-30 (#2 multiplied both sides by -1) #4
A-C= 20 (add #1 & #4) #5
A+C=40 (#3 given)
2A=60 (Add #3 & #5)
A = 30 (divide both sides by 2)
30 + B = 50 (replace A with the answer 30 to #1)
B = 50 - 30 = 20 (subtract 20 from both sides)
30 + C = 40 (replace A with the answer 30 to #3)
C = 40 - 30 = 10 (subtract 30 from both sides)
30–20–10=0 (replace all variables with answers)
the result is equal to zero QED
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40a+20b-90c
20a-40b
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20a-20b-90c
____________
this is answer I hope it helps you.
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