Math, asked by bhuvanakumar01, 3 months ago

Subtract 4a-3b+2c from the sum of 3a+2b+3c and 2a-3b+5c​

Answers

Answered by dyumnagarima
1

Answer:

2a-3b+5c

+3a+2b+3c

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5a-b+8c

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Answered by MяMαgıcıαη
66

{ \bold \orange { \underline{\large{Required \:  Answer :  - }}}} \:

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\large\tt\underline{\green{By\:understanding \:the\:question}}

Firstly let's add  3a + 2b + 3c and  2a - 3b + 5c

: \implies  3a + 2b + 3c + 2a - 3b + 5c

: \implies  3a + 2a + 2b - 3b + 3c + 5c

: \implies  5a - b + 8c

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Now

According to the question :-

Now we had to subtract  4a - 3b + 2c from  5a - b + 8c

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\large\boxed{\red{\tt{So\:let's \:do\:it\::-}}}

: \implies  5a - b + 8c - ( 4a - 3b + 2c )

: \implies  5a - b + 8c - 4a + 3b - 2c

: \implies  5a - 4a - b + 3b + 8c - 2 c

: \implies  a + 2b + 6c

\large\boxed{\pink{\tt{Solved}}}

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