Question

Subtract (4a+6ab+2b-12) from (5a+6ab-3b+24)​

Answer 1

Formula:-

$- \times - = +$

$+ \times + = +$

$+ \times - = -$

$- \times + = -$

${\huge{\mathfrak{\underbrace{\green{Answer-}}}}}$

$(4a+6ab+2b-12) from (5a+6ab-3b+24)$

$= (5a+6ab-3b+24) - (4a+6ab+2b-12)$

$= 5a+6ab-3b+24- 4a - 6ab - 2b + 12$

$= 5a - 4a + 6ab - 6ab - 3b - 2b + 24 + 12$

$= a - 5b + 36$

Hope it helps U✌️✌️✌️..

Answer 2

Question↴↴

Subtract (4a+6ab+2b-12) from (5a+6ab-3b+24)

Answer↴↴

(5a+6ab-3b+24)-(4a+6ab+2b-12)

=5a+6ab-3b+24-4a-6ab-2b+12

=5a-4a+6ab-6ab-3b-2b+24+12

=a-5b+36

Therefore, answer is.......

$\boxed{a-5b+36}$

I hope it helped you☺️✌