Question

Subtract:
4a-7ab +3b+ 12
from 12a-9ab +56-3​

Answer 1

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

we have to substract 4a-7ab+3b+12 from 12a-9ab+56-3

Step by step explanation

We will write 12a-9ab+56-3 first then substract 4a-7ab+3b+12.

Note : Whenever in Question said substract this value from this value then in such case always write first which is written after from and then write before from value with (-) sign because you have to subtract.

come to the question:-

=>4a-7ab+3b+12 from 12a-9ab+56-3

=>12a-9ab+56-3 -(4a-7ab+3b+12)

solving third term (constant)

=>12a-9ab+53-(4a-7ab+3b+12)

Expanding the terms by removing brackets:

=>12a-9ab+53-4a+7ab-3b-12

the value inside brackets when we open the brackets and expand it the sign gets changed.

arranging Variable terms together and constant term together:-

=>12a-4a-9ab+7ab-3b+53-12

=>8ab-2ab-3b+41