Question

subtract -4a -7ab +3b+12 from 12a-9ab+5b-3

Answer 1

Answer:

16a +2b -2ab -15

Step-by-step explanation:

first term = 12a - 9ab + 5b - 3

second term = -4a - 7ab +3b + 12

Now, subtract second term from first implies

(12a - 9ab + 5b - 3) - (-4a - 7ab +3b + 12)

on changing signs of the second bracket as there is a negative sign before it, we get

12a - 9ab + 5b - 3  + 4a + 7ab - 3b -12

Now, operate like terms with like terms

(12a + 4a)  + ( 5b - 3b) + (7ab -9ab) -3 -12

= 16a +2b -2ab -15 is the required answer.

Answer 2

$(12a – 9ab + 5b – 3) – (4a – 7ab + 3b + 12) \\ =  12a – 9ab + 5b – 3 – 4a + 7ab – 3b – 12 \\ =12a – 4a -9ab + 7ab +5b – 3b -3 -12 \\ = 8a – 2ab + 2b – 15$