Question

Subtract 4a – 7ab + 3b + 12 from 12a – 9ab + 5b – 3

Answer 1

Answer:subtract 4a−7ab+3b+12 from 12a−9ab+5b−3

=12a−9ab+5b−3−(4a−7ab+3b+12)

=12a−9ab+5b−3−4a+7ab−3b−12

=8a−2ab+2b−15

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