Question

Subtract 4a-b-ab+3 from the sum of 3a-5b+3ab and 2a+4b-5ab

Answer 1

your answer is as follows
a-ab-3

Answer 2

Given:

A = 4a-b-ab+3    (let)

B = 3a-5b+3ab

C = 2a+4b-5ab

To Find:

value of ( B+C ) - A

Solution:

we have,

A = 4a-b-ab+3    (let)

B = 3a-5b+3ab

C = 2a+4b-5ab

now,

⇒ ( B+C ) - A = ( 3a-5b+3ab + 2a+4b-5ab ) - ( 4a-b-ab+3 )

⇒ ( B+C ) - A = ( 3a-5b+3ab + 2a+4b-5ab ) - 4a + b + ab - 3

⇒ ( B+C ) - A = 3a + 2a - 4a - 5b +4b + b + 3ab - 5ab + ab - 3

⇒ ( B+C ) - A = a - ab - 3

So , The value of ( B+C ) - A = a - ab - 3.