Question

Subtract 4p^2+5q^2-6r^2+7 from 3p^2-4q^2-5r^2-6

Answer 1

4p² + 5q² - 6r² + 7 from 3p² - 4q² - 5r² - 6

We have to subtract

3p² - 4q² - 5r² - 6 - (4p² + 5q² - 6r² +7)

=> 3p² - 4q² - 5r² - 6 - 4p² - 5q² + 6r² - 7

=> 3p² - 4p² - 4q² - 5q² - 5r² + 6r² -7 - 6

=> p² - 9q² + r² - 13

HOPE IT HELP U..........

Answer 2

Answer:

I hope it's helpful to you