Math, asked by yasmeenyasmeen8383, 1 day ago

Subtract   4p^2q – 3pq + 5pq^2 – 8p + 7q – 10 from 18 – 3p – 11q + 5pq – 2pq^2 + 5p^2q​

Answers

Answered by Bhushunb
2

Answer:

= 28 + 5p - 18q + 8pq - 7pq^{2} + p^{2q}

Step-by-step explanation:

4p^{2q} - 3pq + 5pq^{2} - 8p + 7q - 10 from 18 - 3p - 11q + 5pq - 2pq^{2} + 5p^{2q}

Equation formed:

(18 - 3p - 11q + 5pq - 2pq^{2} + 5p^{2q}) - (4p^{2q} - 3pq + 5pq^{2} - 8p + 7q - 10)

sign will change from + to - or vise versa of the second term (4p^{2q} - 3pq + 5pq^{2} - 8p + 7q - 10)

= 18 - 3p - 11q + 5pq - 2pq^{2} + 5p^{2q} - 4p^{2q} + 3pq - 5pq^{2} + 8p - 7q + 10

take like terms with sign

= 18 + 10 - 3p + 8p - 11q - 7q + 5pq + 3pq - 2pq^{2} - 5pq^{2} + 5p^{2q} - 4p^{2q}

= 28 + 5p - 18q + 8pq - 7pq^{2} + p^{2q}

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