subtract 4p²+5q²-6r²+7 from 8p²-4q²-5r²-6
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Answered by
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Answer:4p² + 5q² - 6r² + 7 from 3p² - 4q² - 5r² - 6
We have to subtract
3p² - 4q² - 5r² - 6 - (4p² + 5q² - 6r² +7)
=> 3p² - 4q² - 5r² - 6 - 4p² - 5q² + 6r² - 7
=> 3p² - 4p² - 4q² - 5q² - 5r² + 6r² -7 - 6
=> p² - 9q² + r² - 13
HOPE IT HELP U..........
Step-by-step explanation:
Answered by
1
Answer:
(8p²-4q²-5r²-6)-(4p²+5q²-6r²+7).
8p²-4q²-5r²-6-4p²-5q²+6r²-7. (Because -×+=- & -×-=+).
8p²-4p²-4q²-5q²-5r²+6r²-6-7.
4p²-9q²+1r²-13.
I think this is your answer.
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