Math, asked by BTanisha, 1 year ago

subtract 4p2q-3pq+5pq2-8p+7q-10 from 18-3p-11q+5pq-2pq2+5p2q

Answers

Answered by sprao534
13
Pv2q-3pqv2+8pq-18q+5p+28
Answered by Anonymous
14

(18 – 3p – 11q + 5pq – 2pq2 + 5p2q) – (4p2q – 3pq + 5pq2 – 8p + 7q – 10) \\ </p><p>= 18 – 3p – 11q + 5pq – 2pq2 + 5p2q – 4p2q + 3pq – 5pq2 + 8p – 7q + 10 \\ </p><p>=18+10 -3p+8p -11q – 7q + 5 pq+ 3pq- 2pq^2 – 5pq^2 + 5 p^2 q – 4p^2 q \\ </p><p>= 28 + 5p – 18q + 8pq – 7pq2 + p2q

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